MCQ
The set representing the correct order of ionic radius is
- A$Na^+ > Mg^{2+} > Al^{3+} > Li^+ > Be^{2+}$
- ✓$Na^+ > Li^+ > Mg^{2+} > Al^{3+} > Be^{2+}$
- C$Na^+ > Mg^{2+} > Li^+ > Al^{3+} > Be^{2+}$
- D$Na^+ > Mg^{2+} > Li^+ > Be^{2+}$
In a period, on moving from left to right, the ionic radius decreases. Hence, $N a^{+}>M g^{2+}>A l^{3+}$ and $L i^{+}>B e^{2+}$
In a group, on moving down from top to bottom, the ionic radius increases. Hence, $N a^{+}>L i^{+}$ and $M g^{2+}>B e^{2+}$
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[Molar mass of $\mathrm{KCl}=74.5$ ]
