d $B =\frac{\mu_{0}}{4 \pi} \frac{{idlsin}(\theta)}{ r ^{2}}$
Now by putting Sl units of all measurable quantities in above formula
$\Rightarrow \frac{ W b }{ m ^{2}}=$ $\frac{ \mu_{0}Am }{ m ^{2}}$
$\Rightarrow \mu_0 =\frac{ W b }{ A \cdot m }$
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