The sides of a triangle are 16 cm, 30 cm, 34 cm. Its area is:

Q: The sides of a triangle are $16\ cm, 30\ cm, 34\ cm$. Its area is:

Let $a = 16\ cm, b = 30\ cm, c = 34\ cm$ Semi-perimeter of a triangle $=\frac{\text{a}+\text{b}+\text{c}}{2}=\frac{16+30+34}{2}=40$ Now, $s - a = 24\ cm, s - b = 10\ cm$ and $s - c = 6\ cm$ By Heron's formula. Area of a triangle $=\sqrt{\text{s}(\text{s}-\text{a})(\text{s}-\text{b})(\text{s}-\text{c})}$ $=\sqrt{40\times24\times10\times6}$ $=\sqrt{4\times10\times4\times6\times10\times6}$ $=\sqrt{4^2\times10^2\times6^2}$ $=4\times10\times6$ $= 240\text{cm}^2$ Note: Correct option not given.

M.C.Q

GSEB - English Medium

The sides of a triangle are $16\ cm, 30\ cm, 34\ cm$. Its area is:

A$225\text{cm}^2$
B$225\sqrt{3}\text{cm}^2$
C$225\sqrt{2}\text{cm}^2$
D$450\text{cm}^2$

STD 9
Maths
Herons Formula
RD Sharma

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Download App

Download our appand get started for free

Similar Questions

Download our app
and get started for free