If each side of an equilateral triangle of area A is doubled, then the area of new triangle is
A$2 A$
B$4 A$
C$8 A$
D$6 A$
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B$4 A$
(b) $4 A$ Let $a$ be the length of each side of the triangle. Then, $\Lambda=\frac{\sqrt{3}}{4} a^2$. Let $A^{\prime}$ be the area of the triangle whose each side is $2 a$. Then, $A^{\prime}=\frac{\sqrt{3}}{4}(2 a)^2=4\left(\frac{\sqrt{3}}{4} a^2\right)=4 A$
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