MCQ
The simplest form of $0.12\overline{3}$ is:
- A$\frac{41}{330}$
- B$\frac{37}{330}$
- C$\frac{41}{333}$
- ✓None of these.
✓
Answer
Correct option: D.
None of these.
Let $\text{x}=0.12\overline{3}$
Then, $\text{x}=0.12333 \ ...(\text{i})$
$\therefore100\text{x}=12.333... \ (\text{ii})$
and $1000\text{x}=123.333... \ (\text{iii})$
On subtracting $(ii)$ from $(iii)$, we get
$900\text{x}=111$
$\Rightarrow\text{x}=\frac{111}{900}=\frac{37}{300}$
Then, $\text{x}=0.12333 \ ...(\text{i})$
$\therefore100\text{x}=12.333... \ (\text{ii})$
and $1000\text{x}=123.333... \ (\text{iii})$
On subtracting $(ii)$ from $(iii)$, we get
$900\text{x}=111$
$\Rightarrow\text{x}=\frac{111}{900}=\frac{37}{300}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The following marks were obtained by the students in a test:
$81, 72, 90, 90, 86, 85, 92, 70, 71, 83, 89, 95, 85, 79, 62$
The range of the marks is:
→$81, 72, 90, 90, 86, 85, 92, 70, 71, 83, 89, 95, 85, 79, 62$
The range of the marks is:
In fig., $\triangle\text{ABD}\cong\triangle\text{ACD},$ $AB = AC, BD = DC$ name the criteria by which the triangles are congruent:
→If $(4, 19)$ is a solution of the equation $y = ax + 3$, then $a =$
→The mean of $100$ observations is $50$. If one of the observations which was $50$ is replaced by $150$, the resulting mean will be:
→Write the correct answer in the following:
Signs of the abscissa and ordinate of a point in the second quadrant are respectively:
Signs of the abscissa and ordinate of a point in the second quadrant are respectively:
Axioms are assumed:
In a $\triangle\text{ABC},$ if $\text{AB}=\text{AC}$ and BC is produced to D such that $\angle\text{ACD}=100^\circ$ then $\angle\text{A}=$
→In $\triangle\text{ABC},$ if $\angle\text{C}>\angle\text{B},$ then
→Find the measure of each exterior angle of an equilateral triangle.
If each side of a cube is doubled, then its volume: