MCQ
The sinusoidal potential difference $V_1$ shown in figure applied across a resistor $R$ produces heat at a rate $W$. What is the rate of heat dissipation when the square wave potential difference $V_2$ as shown in figure is applied across the resistor?
  • A
    $\frac{W}{2}$
  • B
    $W$
  • C
    $\sqrt{2} W$
  • $2 W$

Answer

Correct option: D.
$2 W$
d
(d)

$\operatorname{Power}(P)=\frac{V_{ ms }^2}{R}$

According to the problem

$w=\frac{\left(\frac{V_0}{\sqrt{2}}\right)^2}{R}$

for square wave $V_{ rms }=V_0$

$W^{\prime}=\frac{V_0^2}{R}$

$\frac{W^{\prime}}{W}=2, \quad W^{\prime}=2\, W$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free