MCQ
The solubility product of a sparingly soluble salt $AB$ at room temperature is $1.21 \times 10^{-6},$ its molar solubility is :
- A$1.21 \times 100M.$
- B$1.1 \times 10^{-4}M.$
- ✓$1.1 \times 10^{-3}M.$
- DNone of these.
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$\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - C - COOH} \\
{\,\,\,\,\,\,\,\,||} \\
{\,\,\,\,\,\,\,\,\,\,\,\,C{H_2}}
\end{array}$
is :