MCQ
The solubility product of $AgCl$ is $10^{-10}\, M^2$. The minimum volume (in $m^3$) of water required to dissolve $14.35\, mg$ of $AgCl$ is approximately
- ✓$10$
- B$0.1$
- C$100$
- D$0.01$
$\quad S \quad S$
$\Rightarrow K_{s p}=S^{2}$
$\Rightarrow 10^{-10}=S^{2} \quad ; \quad S=10^{-5} \,M$
$\Rightarrow$ Molecular weight of $A g C l=143.5 \,g$
$\Rightarrow 10^{-5}=\frac{14.35 \times 10^{-3}}{143.5} \times \frac{1000}{V(m l)}$
$10^{-1}=\frac{1000}{V(m l)}$
$V_{m l}=10000 ml =10\,litres$
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$N _2 O _3, N _2 O _5, P _4 O _6, P _4 { O }_7, H _4 P _2 O _5, H _5 P _3 O _{10}, H _2 S _2 O _3, H _2 S _2 O _5$
$CS_2 + 3O_2 \to 2SO_2 + CO_2$