MCQ
The solubility product of $Hg_2I_2$ is equal to
- A$\left[ {Hg_2^{ + 2}} \right]\left[ {{I^ - }} \right]$
- B$\left[ {H{g^{ + 2}}} \right]\left[ {{I^ - }} \right]$
- ✓$\left[ {H{g_2}^{ + 2}} \right]{\left[ {{I^ - }} \right]^2}$
- D${\left[ {H{g^{ + 2}}} \right]^2}{\left[ {{I^ - }} \right]^2}$