MCQ
The solution of $\frac{{{d^2}y}}{{d{x^2}}} = \cos x - \sin x$is
- ✓$y = - \cos x + \sin x + {c_1}x + {c_2}$
- B$y = - \cos x - \sin x + {c_1}x + {c_2}$
- C$y = \cos x - \sin x + {c_1}{x^2} + {c_2}x$
- D$y = \cos x + \sin x + {c_1}{x^2} + {c_2}x$
$\frac{{dy}}{{dx}} = \sin x + \cos x + {c_1}$
Again $y = - \cos x + \sin x + {c_1}x + {c_2}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$[cot \,\theta ] x + y = 0$