The solution of dy dx =1+x+y+xy is: - Vidyadip

MCQ

The solution of $\frac{\text{dy}}{\text{dx}}=1+\text{x}+\text{y}+\text{xy}$ is:

A
$\text{x}-\text{y}=\text{k}(1+\text{xy})$
✓
$\log(1+\text{y})=\text{x}+\frac{\text{x}^2}{2}+\text{k}$
C
$\log(1+\text{y})=\text{x}+\frac{\text{y}^2}{2}=\text{k}$
D
None of these

✓

Answer

Correct option: B.

$\log(1+\text{y})=\text{x}+\frac{\text{x}^2}{2}+\text{k}$

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