MCQ
The solution of $\text{x}^{2}+\text{y}^{2}\frac{\text{dy}}{\text{dx}}=4$ is:
- A$x^2+y^2=12 x+C$
- B$x^2+y^2=3 x+C$
- C$x^3+y^3=3 x+c$
- ✓$x^3+y^3=12 x+C$
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