MCQ
The solution of the differential equation $\left(x^2+1\right) \frac{d y}{d x}+\left(y^2+1\right)=0$, is
  • $y=\frac{1-x}{1+x}$
  • B
    $y=\frac{1+x}{1-x}$
  • C
    $y=2+x^2$
  • D
    $Y x( x -1)$

Answer

Correct option: A.
$y=\frac{1-x}{1+x}$
(a) $y=\frac{1-x}{1+x}$
Explanation: $y=\frac{1-x}{1+x}$

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