MCQ
The solution of the differential equation $\frac{\text{dy}}{\text{dx}}=\frac{\text{x}}{1+\text{x}^2}$ is:
- A$\text{y}=\frac{1}{2}\log|2+\text{x}^2|+\text{c}$
- B$\text{y}=\frac{1}{2}\log(1+\text{x})+\text{c}$
- ✓$\text{y}=\log\Big(\sqrt{1+\text{x}^2}\Big)+\text{c}$
- DNone of these