- A$[Co(CN)_6]^{4-}$
- B$[Cr(H_2O)_6)^{3+}$
- ✓$[FeCl_4]^{2-}$
- D$[Fe(H_2O)_6)^{3+}$
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$\mathop {C{H_3} - \mathop C\limits^ \oplus H - C{H_3}}\limits_I $
$\mathop {C{H_3} - \mathop C\limits^ \oplus H - OC{H_3}}\limits_{II} $
$\mathop {C{H_3} - \mathop C\limits^ \oplus H - C{H_2} - OC{H_3}}\limits_{III} $
(Given atomic number $\mathrm{Sc}: 21, \mathrm{Ti}: 22, \mathrm{~V}: 23, \mathrm{Cr}$ : $24, \mathrm{Mn}: 25, \mathrm{Fe}: 26)$
Above reaction is an example of

$(I)$ ${H_2}(g) + \frac{1}{2}{O_2}(g) \to {H_2}O(l);$
$\Delta {H^o_{298\,K}} = - 285.9\,kJ\,mo{l^{ - 1}}$
$(II)$ ${H_2}(g) + \frac{1}{2}{O_2}(g) \to {H_2}O(g);$
$\Delta {H^o_{298\,K}} = - 241.8\,kJ\,mo{l^{ - 1}}$
The molar enthalpy of vapourisation of water will be.....$kJ\,mol^{-1}$
$A \rightarrow B; \ \ \ K_1 = 10^{15}\ exp.\ \left( {\frac{{ - 2000}}{T}} \right)$
$C \rightarrow D;\ \ \ K_2 = 10^{14}\ exp. \ \left( {\frac{{ - 1000}}{T}} \right)$
The temperature at which $K_1 = K_2$ is ........... $K$ ($exp. = e$)