The spectral emissive power $E_\lambda $ for a body at temperature $T_1$ is plotted against the wavelength and area under the curve is found to be $A$. At a different temperature $T_2$ the area is found to be $9A$. Then $\lambda _1/\lambda _2 =$
  • A$3$
  • B$1/3$
  • C$1/\sqrt 3 $
  • D$\sqrt 3 $
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