The square loop $ABCD$, carrying a current $i$, is placed in uniform magnetic field $B$, as shown. The loop can rotate about the axis $XX$'. The plane of the loop makes and angle $\theta$ ($\theta$ $< 90^o$) with the direction of $B$. Through what angle will the loop rotate by itself before the torque on it becomes zero
Medium
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(c) In the position shown, $AB$ is outside and $CD$ is inside the plane of the paper.
The Ampere force on $AB$ acts into the paper.
The torque on the loop will be clockwise, as seen from above.
The loop must rotate through an angle $({90^o} + \theta )$ before the plane of the loop becomes normal to the direction of the direction of $B$ and the torque becomes zero.
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