- ✓$-650$
- B$+650$
- C$-680$
- D$-620$
$\Delta {\text{H}} = [4 \times ( - 94) + 3 \times ( - 68)] - [ - 30] + $
$10 - 4 \times 20 - 3 \times 10$
$=-650\, \mathrm{kcal} / \mathrm{mol}$
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$HI \rightleftharpoons \frac {1}{2} H_{2(g)} + \frac{1}{2} I_{2(g)}$
is $8.0$. The equilibrium constant of the reaction
$H_{2( g )} + I_{2(g)} \rightleftharpoons 2HI_{ ( g )}$ will be
| Substance | $H _{2}$ | $C ($ graphite $)$ | $C _{2} H _{6}( g )$ |
| $\frac{\Delta_{ C } H ^{\Theta}}{ kJmol ^{-1}}$ | $-286.0$ | $-394.0$ | $-1560.0$ |
The enthalpy of formation of ethane is ........ .
$A + B \rightleftharpoons C + D$ is $1 \times 10^{-2}$ at $298\, K$ and is
$2$ at $273\, K$. The chemical process resulting in the formation of $C$ and $D$ is
$N{H_4}HS(s) \rightleftharpoons N{H_3}(g) + {H_2}S(g)$
Predict the effect of adding the inert gas
$A : 1s^2\, 2s^2\, 2p^6$
$B : 1s^2\, 2s^2\, 2p^6\, 3s^2\, 3p^3$
$C : 1s^2\, 2s^2\, 2p^6\, 3s^2\, 3p^5$