The string of a violin emits a note of $205 \,Hz$ at its correct tension. The string is tightened slightly and then it produces six beats in two seconds with a tuning fork of frequency $205 Hz$. The frequency of the note emitted by the taut string is .......... $Hz$
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(c)
Initial frequency $=205 \,Hz$
String tightned so frequency is increased $=205+f$
Final frequency of string $-$ frequency of tuning fork $=3$ beats
$205+f-205=3$
$\therefore f=3$
$\therefore$ Final frequency $=205+3=208 \,Hz$
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