MCQ
The successive Ionisation energies of an element $(A)$ is given as $IE_1 = 20\,ev\,, IE_2 = 45\,ev, IE_3 = 150\,ev, IE_4 = 900\,ev, IE_5 = 1800\, ev$ Formula of halide of $(A)$ is
- A$AX$
- ✓$AX_3$
- C$AX_4$
- D$AX_5$
✓
Answer
Correct option: B.
$AX_3$
b
Longest jump $-1=$ Removed No. of electrons
Longest jump $-1=$ Removed No. of electrons
$4-1=3 e^{-}$ are removed
$\therefore \quad A^{+3} \quad \operatorname{lan}=A X_{3}$
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