8 , mol of AB_3(g) are introduced into a 1.0 , dm^3 vessel. If it… - Vidyadip

MCQ

$8\, mol$ of $AB_3(g)$ are introduced into a $1.0\, dm^3$ vessel. If it dissociates as

$2A{B_3}(g) \rightleftharpoons {A_2}(g) + 3{B_2}(g)$. At equilibrium, $2\, mol$ of $A_2$ are found to be present. The equilibrium constant of this reaction is

A
$2$
B
$3$
✓
$27$
D
$36$

✓

Answer

Correct option: C.

$27$

c
$\mathop {\,\,}\limits_{\mathop {at\,t = 0}\limits_{at\,eq.} } \mathop {\,\mathop {\mathop {2A{B_3}(g)}\limits_8 }\limits_{(8 - 2 \times 2)} }\limits_{ = 4} \leftrightarrow \mathop {\mathop {\mathop {{A_2}(g)}\limits_0 }\limits_2 }\limits_2 + \mathop {\mathop {\mathop {3{B_2}(g)}\limits_0 }\limits_{3 \times 2} }\limits_6 $

now ${K_C} = \frac{{[{A_2}]{{[{B_2}]}^3}}}{{{{[A{B_3}]}^2}}} = \frac{{2/1 \times {{[6/1]}^3}}}{{{{[4/1]}^2}}} = 27$

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