MCQ
The sum $1(1!) + 2(2!) + 3(3!) + ....+n (n!)$ equals
- A$3\,(n\,!)\, + \,n - 3$
- B$(n + 1)!\, - \,(n - 1)!$
- ✓$(n + 1)\,!\, - 1$
- D$2\,(n\,!) - 2n - 1$
=$(2 - 1)(1!) + (3 - 1)(2!) + (4 - 1)(3!) + .....$$ + [(n + 1) - 1](n!)$
= $(2.1! - 1!) + (3.2! - 2!) + (4.3! - 3!) + ....$$ + [(n + 1)(n!) - (n!)]$
=$(2! - 1!) + (3! - 2!) + (4! - 3!) + .... + [(n + 1)! - (n)!]$
= $(n + 1)! - 1!$.
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