MCQ
The sum $\frac{7}{8}+\frac{1}{9}$ is between
  • A
    $\frac{1}{2} \text{and} \frac{3}{4}$
  • $\frac{3}{4} \text{and} 1$
  • C
    $1 \text{and} 1\frac{1}{4}$
  • D
    $1\frac{1}{4} \text{and} 1\frac{1}{2}$

Answer

Correct option: B.
$\frac{3}{4} \text{and} 1$
 The $LCM$ of the denominators of the given sum $\frac{7}{8}+\frac{1}{9}$ is $72,$ therefore, the sum can be rewritten as follows:
$\frac{7 \times 9}{8 \times 9}+\frac{1\times8}{9\times8}=\frac{63}{72}+\frac{8}{72}=\frac{71}{72}$
Since, $\frac{71}{72}<1$
Hence, the sum $\frac{7}{8}+\frac{1}{9}$ lies between $\frac{3}{4}$​ and $1.$

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