MCQ
The sum, $\sum\limits_{n=1}^{7} \frac{n(n+1)(2 n+1)}{4}$ is equal to
- A$521$
- B$663$
- ✓$504$
- D$429$
$=\frac{1}{4}\left(2\left(\frac{7 \times 8}{2}\right)^{2}+3\left(\frac{7 \times 8 \times 15}{6}\right)+\frac{7 \times 8}{2}\right)$
$=504$
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Where $\alpha \in R$, then the value of $16 \alpha$ is equal to
$(A)$ $\frac{2 \log _3 2}{2 \log _3 2-1}$ $(B)$ $\frac{2}{2-\log _2 3}$ $(C)$ $\frac{1}{1-\log _4 3}$ $(D)$ $\frac{2 \log _2 3}{2 \log _2 3-1}$
