Download App

Surface Areas and Volumes — Maths STD 10 — Question

CBSE BoardEnglish MediumSTD 10MathsSurface Areas and Volumes1 Mark
MCQ
The surface area of a cube is $216 cm^2$,its volume is
  • A
    $144 cm^3$
  • B
    $196 cm^3$
  • C
    $212 cm^3$
  • ✓
    $216 cm^3$
✓

Answer

Correct option: D.
$216 cm^3$
(d)
Let the length of each side of the cube be a cm. Then,
Surface area = $216 cm^2 \Rightarrow 6 a^2=216 \Rightarrow a^2=36 \Rightarrow a=6$
Volume $=a^3=6^3 cm^3=216 cm^3$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Surface Areas and Volumes→Surface Areas and Volumes — all question types→Maths STD 10 question papers→CBSE Board STD 10 question papers→CBSE Board question paper generator→

Similar questions

The number of terms of the A.P. $3,7,11,15, \ldots$ to be taken so that the sum is 406 is
→
If the area of the triangle formed by the points $(x, 2 x),(-2,6)$ and $(3,1)$ is 5 square units, then $x=$
→
The roots of the equation $8 x^2-22 x-21=0$ are
→
From a light house the angles of depression of two ships on opposite sides of the light house are observed to be $30^\circ$ and $45^\circ$ . If the height of the light house is $h$ metres, the distance between the ships is :
→
$\triangle\text{ABC}$ is such that $AB = 3\ cm, BC = 2\ cm$ and $CA = 2.5\ cm$. If $\triangle\text{DEF}\sim\triangle\text{ABC}$ and $EF = 4\ cm,$ then perimeter of $\triangle\text{DEF}$ is :
→
Which term of the $AP 72, 63 54, ....$ is $0?$
→
Which of the following cannot be determined graphically?
→
The marks obtained by $9$ students in Mathematics are $59, 46, 30, 23, 27, 40, 52, 35$ and $29.$ The median of the data is
→
The prime factors of $196$ are
→
In a $\triangle A B C$, perpendicular $A D$ from $A$ on $B C$ meets $B C$ at $D$. If $B D=8 cm, D C=2 cm$ and $A D=4 cm$, then
→