MCQ
The surface area of a cube whose volume is $64 \mathrm{~cm}^3$ is :
- A$108 \mathrm{~cm}^2$
- B$72 \mathrm{~cm}^2$
- ✓$96 \mathrm{~cm}^2$
- D$64 \mathrm{~cm}^2$
✓
Answer
Correct option: C.
$96 \mathrm{~cm}^2$
Given : Volume of cube $=64 \mathrm{~cm}^3$
$\Rightarrow a^ 3=64$
$\Rightarrow a^3=(4)^3$
$\Rightarrow a=4 \mathrm{~cm}$
$\therefore$ Surface Area of cube $=6 a^2$
$=6(4)^2=96\ \mathrm{sq} . \mathrm{cm}$
$\Rightarrow a^ 3=64$
$\Rightarrow a^3=(4)^3$
$\Rightarrow a=4 \mathrm{~cm}$
$\therefore$ Surface Area of cube $=6 a^2$
$=6(4)^2=96\ \mathrm{sq} . \mathrm{cm}$
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