The surface tension of a liquid is $70\,dyne/cm$. In $MKS$ system its value is
Easy
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Two resistors ${R}_{1}=(4 \pm 0.8) \Omega$ and ${R}_{2}=(4 \pm 0.4)$ $\Omega$ are connected in parallel. The equivalent resistance of their parallel combination will beView Solution
- 2$10\; amu =$ ……..$kg$View Solution
- 3Time intervals measured by a clock give the following readings :View Solution
$1.25 \;s , 1.24\; s , 1.27\; s , 1.21 \;s$ and $1.28\; s$
What is the percentage relative error of the observations?
- 4The length, breadth and thickness of a strip are $(10.0 \pm 0.1)\; cm ,(1.00 \pm 0.01) \;cm$ and $(0.100 \pm 0.001)\; cm$ respectively. The most probable error in its volume will be?View Solution
- 5View SolutionThe dimensions of universal gravitational constant are
- 6View SolutionUnit of energy is
- 7Two resistors of resistances $R_1 = (100 \pm 3) \,\Omega $ and $R_2 = (200 \pm 4)$ are connected in series. The maximm absolute error and percentage error in equivalent resistance of the series combination isView Solution
- 8If pressure $P$, velocity $V$ and time $T$ are taken as fundamental physical quantities, the dimensional formula of force isView Solution
- 9Given below are two statements: One is labelled as Assertion $(A)$ and other is labelled as Reason $(R)$.View Solution
Assertion $(A)$ : Time period of oscillation of a liquid drop depends on surface tension $(S)$, if density of the liquid is $p$ and radius of the drop is $r$, then $T = k \sqrt{ pr ^{3} / s ^{3 / 2}}$ is dimensionally correct, where $K$ is dimensionless.
Reason $(R)$: Using dimensional analysis we get $R.H.S.$ having different dimension than that of time period.
In the light of above statements, choose the correct answer from the options given below.
- 10In an experiment, the values of refractive indices of glass were found to be $1.54, 1.53,$$1.44,1.54,1.56$ and $1.45$ in successive measurements, then Mean absolute error isView Solution