MCQ
The system $Kx - y =2$ and $6 x -2 y =3$ has a unique solution only when
- A$K =0$
- B$K \neq 0$
- C$K =3$
- ✓$K \neq 3$
✓
Answer
Correct option: D.
$K \neq 3$
For a unique solution, we have
$\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$
$\therefore \frac{K}{6} \neq \frac{-1}{-2} $
$\Rightarrow K \neq 3$
$\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$
$\therefore \frac{K}{6} \neq \frac{-1}{-2} $
$\Rightarrow K \neq 3$
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