MCQ
The system $x -2 y =3$ and $3 x + Ky =1$ has a unique solution only when
  • $K =-6$
  • B
    $K \neq-6$
  • C
    $K =0$
  • D
    $K \neq 0$

Answer

Correct option: A.
$K =-6$
(a)
For a unique solution,
We have, $\frac{ a _1}{ a _2} \neq \frac{ b _1}{b_2}$
So $\frac{1}{3} \neq \frac{-2}{K} \Rightarrow K \neq-6$

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