The teacher instructed three students $‘A’, ‘B’$ and $‘C’$ respectively to prepare a $50 \%$ (mass by volume) solution of sodium hydroxide $(NaOH)$. $‘A’$ dissolved $50g$ of $NaOH$ in $100\ mL$ of water, $‘B’$ dissolved $50\ g$ of $NaOH$ in $100\ g$ of water while $‘C’$ dissolved $50\ g$ of $NaOH$ in water to make $100\ mL$ of solution. Which one of them has made the desired solution and why?
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Student $'C'$ has made the desired solution. $\text{Mass by volume%}=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times200$
$=\frac{50\text{g}}{100\text{ml}}\times100=50\%\text{mass by volume}$
$=\frac{50\text{g}}{100\text{ml}}\times100=50\%\text{mass by volume}$
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