The temperature at which the speed of sound in air becomes double of its value at ${0^o}C$ is ...... $K$
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$v \propto \sqrt T $
==>$\sqrt {\frac{{{T_2}}}{{{T_1}}}} = \frac{{{v_2}}}{{{v_1}}} $
$\Rightarrow {T_2} = {T_1}{\left( {\frac{{{v_2}}}{{{v_1}}}} \right)^2}$
$ \Rightarrow {T_2} = 273 \times 4 = 1092K$
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