The temperature of a hypothetical gas increases to $\sqrt 2 $ times when compressed adiabatically to half the volume. Its equation can be written as
Medium
Download our app for free and get startedPlay store
(a) $T{V^{\gamma - 1}}$= constant
$\therefore  \frac{{{T_1}}}{{{T_2}}} = {\left( {\frac{{{V_2}}}{{{V_1}}}} \right)^{\gamma - 1}}$or ${\left( {\frac{1}{2}} \right)^{\gamma - 1}} = \sqrt {\frac{1}{2}} $
 $\therefore \gamma - 1 = \frac{1}{2}$or $\gamma = \frac{3}{2}$

$P{V^{3/2}}$= constant

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    $0.02\, moles$ of an ideal diatomic gas with initial temperature $20^{\circ} C$ is compressed from $1500 \,cm ^{3}$ to $500 \,cm ^{3}$. The thermodynamic process is such that $p V^{2}=\beta$, where $\beta$ is a constant. Then, the value of $\beta$ is close to (the gas constant, $R=8.31 \,J / K / mol$ ).
    View Solution
  • 2
    The temperature-entropy diagram of a reversible engine cycle is given in the figure. Its efficiency is
    View Solution
  • 3
    A sample of an ideal gas is taken through the cyclic process $ABCA$ as shown in figure. It absorbs, $40\,J$ of heat during the part $A B$, no heat during $BC$ and rejects $60\,J$ of heat during $CA$. $A$ work $50\,J$ is done on the gas during the part $BC$. The internal energy of the gas at $A$ is $1560\,J$. The work done by the gas during the part $CA$ is.............$J$
    View Solution
  • 4
    The specific heat capacity of a metal at low temperature $(T)$ is given as $C_p=32\left(\frac{ T }{400}\right)^{3}\;kJ\,k ^{-1}\, kg ^{-1}$. A $100\; g$ vessel of this metal is to be cooled from $20 \;K$ to $4\; K$ by a special refrigerator operating at room temperature $27^\circ c$). The amount of work required to cool the vessel is
    View Solution
  • 5
    A solid body of constant heat capacity $1\ J/^o C$ is being heated by keeping it in contact with reservoirs in two ways :

    $(i)$ Sequentially keeping in contact with $2$ reservoirs such that each reservoir supplies same amount of heat.

    $(ii)$ Sequentially keeping in contact with $8$ reservoirs such that each reservoir supplies same amount of heat.

    In both the cases body is brought from initial temperature $100^o C$ to final temperature $200^o C$. Entropy change of the body in the two cases respectively is :

    View Solution
  • 6
    The above $P-V$ diagram represents the thermodynamic cycle of an engine, operating with an ideal monatomic gas. The amount of heat, extracted from the source in a single cycle is
    View Solution
  • 7
    Consider a process shown in the figure. During this process the work done by the system
    View Solution
  • 8
    Match the thermodynamic processes taking place in a system with the correct conditions. In the table: $\Delta Q$ is the heat supplied, $\Delta W$ is the work done and $\Delta U$ is change in internal energy of the system
    Process Condition
    $(I)$ Adiabatic $(A)\; \Delta W =0$
    $(II)$ Isothermal $(B)\; \Delta Q=0$
    $(III)$ Isochoric $(C)\; \Delta U \neq 0, \Delta W \neq 0 \Delta Q \neq 0$
    $(IV)$ Isobaric $(D)\; \Delta U =0$
    View Solution
  • 9
    $1\,kg$ of water at $100\, ^{\circ}C$ is converted into steam at $100^{\circ}\,C$ by boiling at atmospheric pressure. The volume of water changes from $1.00 \times 10^{-3}\,m ^3$ as a liquid to $1.671\,m ^3$ as steam. The change in internal energy of the system during the process will be $........kJ$ (Given latent heat of vaporisaiton $=2257\,kJ / kg$. Atmospheric pressure $=1 \times 10^5\,Pa$ )
    View Solution
  • 10
    A van der Waal's gas obeys the equation of state $\left(p+\frac{n^2 a}{V^2}\right)(V-n b)=n R T$. Its internal energy is given by $U=C T-\frac{n^2 a}{V}$. The equation of a quasistatic adiabat for this gas is given by
    View Solution