The temperature of a liquid drops from $365K$ to $361 K$ in $2$ minutes. Find the time during which temperature of the liquid drops from $344\;K$ to $342K$. Temperature of room is $293\;K$ ....... $\sec$
Diffcult
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(a) $\frac{{365 - 361}}{2}$$ = K\left[ {\frac{{365 + 361}}{2} - 293} \right]= 70 K$
==> $K = \frac{1}{{35}}$
Again $\frac{{344 - 342}}{t} = \frac{1}{{35}}\left[ {\frac{{344 - 342}}{2} - 293} \right] = \frac{{10}}{7}$
==> $t = \frac{{14}}{{10}}$min = $\frac{{14}}{{10}} \times 60 = 84$sec.
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