The three processes in a thermodynamic cycle shown in the figure are : Process $1 \rightarrow 2$ is isothermal; Process $2 \rightarrow 3$ is isochoric (volume remains constant); Process $3 \rightarrow 1$ is adiabatic. The total work done by the ideal gas in this cycle is $10 \,J$. The internal energy decreases by $20 \,J$ in the isochoric process. The work done by the gas in the adiabatic process is $-20 \,J$. The heat added to the system in the isothermal process is .............. $J$
KVPY 2013, Medium
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A sample of $0.1\, g$ of water at $100^o C$ and normal pressure $(1.013 \times 10^5 N m^{-2} )$ requires $54\ cal $ of heat energy to convert to steam at $100^o C.$ If the volume of the steam produced is $167.1 \,cc,$ the change in internal energy of the sample, is ....... $J$View Solution
- 2An ideal gas heat engine operates in a Carnot cycle between $227^o C$ and $127^o C$. It absorbs $6\,kcal$ at the higher temperature. The amount of heat (in $kcal$) converted into work is equal toView Solution
- 3The gas law $\frac{{PV}}{T} = $ constant is true forView Solution
- 4View SolutionAn ideal gas, undergoing adiabatic change, has which of the following pressure temperature relationship?
- 5View SolutionNeon gas of a given mass expands isothermally to double volume. What should be the further fractional decrease in pressure, so that the gas when adiabatically compressed from that state, reaches the original state?
- 6Match the thermodynamic processes taking place in a system with the correct conditions. In the table: $\Delta Q$ is the heat supplied, $\Delta W$ is the work done and $\Delta U$ is change in internal energy of the systemView Solution
Process Condition $(I)$ Adiabatic $(A)\; \Delta W =0$ $(II)$ Isothermal $(B)\; \Delta Q=0$ $(III)$ Isochoric $(C)\; \Delta U \neq 0, \Delta W \neq 0 \Delta Q \neq 0$ $(IV)$ Isobaric $(D)\; \Delta U =0$ - 7An ideal gas undergoes change in its state from the initial state $I$ to the final state $F$ via two possible paths as shown below. Then,View Solution
- 8Match List $I$ with List $II$ :View Solution
List $I$ List $II$ $A$ Isothermal Process $I$ Work done by the gas decreases internal energy $B$ Adiabatic Process $II$ No change in internal energy $C$ Isochoric Process $III$ The heat absorbed goes partly to increase internal energy and partly to do work $D$ Isobaric Process $IV$ No work is done on or by the gas Choose the correct answer from the options given below :
- 9View SolutionThe work done in which of the following processes is zero
- 10One mole of an ideal gas $(\gamma = 1.4)$ is adiabatically compressed so that its temperature rises from $27\,^oC$ to $35\,^oC$. The change in the internal energy of the gas is .... $J$ (given $R = 8.3 \,J/mole/K$)View Solution