A person with his hands in his pockets is skating on ice at the velocity of $10 \,m/s$ and describes a circle of radius $50\, m$. What is his inclination with vertical
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(d) The inclination of person from vertical is given by,
$\tan \theta = \frac{{{v^2}}}{{rg}} = \frac{{{{(10)}^2}}}{{50 \times 10}} = \frac{1}{5}$
$⇒$ $\theta = {\tan ^{ - 1}}(1/5)$
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