The three resistances A, B and C have values 3R, 6R and R respectively. When some potential difference is applied across the network, the thermal

Q: The three resistances $A, B$ and $C$ have values $3R, 6R$ and $R$ respectively. When some potential difference is applied across the network, the thermal powers dissipated by $A, B$ and $C$ are in the ratio

c (c)Thermal power in $A = {P_A} = {\left( {\frac{{2i}}{3}} \right)^2}3R = \frac{4}{3}{i^2}R$ Thermal power in $B = {P_B} = {\left( {\frac{i}{3}} \right)^2}6R = \frac{2}{3}{i^2}R$ Thermal power in $C = {P_C} = {i^2}R$ $ \Rightarrow {P_A}:{P_B}:{P_C}$ $ = \frac{4}{3}:\frac{2}{3}:1 = 4:2:3$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

The three resistances $A, B$ and $C$ have values $3R, 6R$ and $R$ respectively. When some potential difference is applied across the network, the thermal powers dissipated by $A, B$ and $C$ are in the ratio

A$2 : 3 : 4$
B$2 : 4 : 3$
C$4 : 2 : 3$
D$3 : 2 : 4$

Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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