MCQ
The threshold frequency of a metal with work function $6.63\ \mathrm{eV}$ is:
- A$16 \times 10^{1 \mathrm{~s}} \mathrm{~Hz}$
- B$16 \times 10^{12} \mathrm{~Hz}$
- C$1.6 \times 10^{12} \mathrm{~Hz}$
- ✓$1.6 \times 10^{15} \mathrm{~Hz}$
✓
Answer
Correct option: D.
$1.6 \times 10^{15} \mathrm{~Hz}$
d
$ \phi_0=h v_0 $
$ \phi_0=h v_0 $
$ 6.63 \times 1.6 \times 10^{-19}=6.63 \times 10^{-34} v_0 $
$ v_0=\frac{1.6 \times 10^{-19}}{10^{-34}} $
$ v_0=1.6 \times 10^{15} \mathrm{~Hz}$
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