Energy radiated from a black body is given by
$U=\sigma \cdot A \cdot T^4 \cdot t$
where, $\sigma=$ Stefan's constant, $A=$ area, $T=$ absolute temperature and $t=$ time.
Now, ratio of energy collected in two given cases is
$\frac{U_2}{U_1} =\frac {(A / 2)(2 T)^4} {A T^4}=8$
Hence, ratio of temperature rise of water is
$\frac{m s \Delta T_2}{m s \Delta T_1}=\frac{U_2}{U_1}=8 .$
$\Rightarrow \quad \Delta T_2=8 \Delta T_1$
$\text { As, } \Delta T_1=1^{\circ} C \text { and } \Delta T_2=8^{\circ} C .$
So, temperature of water increases from $10^{\circ} C$ to $18^{\circ} C .$

[Given: Wien's constant as $2.9 \times 10^{-3} \mathrm{~m}-\mathrm{K}$ and $\frac{\mathrm{hc}}{\mathrm{e}}=1.24 \times 10^{-6} \mathrm{~V}-\mathrm{m}$ ]
| List-$I$ | List-$II$ |
| ($P$) $2000 \mathrm{~K}$ | ($1$) The radiation at peak wavelength can lead to emission of photoelectrons from a metal of work function $4 \mathrm{eV}$ |
| ($Q$) $3000 \mathrm{~K}$ | ($2$) The radiation at peak wavelength is visible to human eye. |
| ($R$) $5000 \mathrm{~K}$ | ($3$) The radiation at peak emission wavelength will result in the widest central maximum of a single slit diffraction. |
| ($S$) $10000 \mathrm{~K}$ | ($4$) The power emitted per unit area is $1 / 16$ of that emitted by a blackbody at temperature $6000 \mathrm{~K}$. |
| ($5$) The radiation at peak emission wavelength can be used to image human bones. |