The total energy of a particle executing simple harmonic motion is
  • A$\propto \,x$
  • B$\propto \,x^2$
  • Cindependent of $x$
  • D$\propto x^{1/2}$
Easy
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    The value of maximum possible amplitude in the case of forced oscillations when driving frequency is close to natural frequency is
    View Solution
  • 2
    A simple pendulum is released from rest at the horizontally stretched position. When the string makes an angle $\theta$ with the vertical, the angle $\phi$ which the acceleration vector of the bob makes with the string is given by
    View Solution
  • 3
    A simple pendulum having length $\ell $ is having speed  $\sqrt {2g\ell }$ at bottom most point of its trajectory. Its motion will be
    View Solution
  • 4
    A particle moves in space according to equation

    $\vec r = (\sin \,t\,\hat i\, + \,\cos \,t\,\hat j\, + \,t\,\hat k)m$

    Find time $'t'$ when position vector and acceleration vector are perpendicular to each other

    View Solution
  • 5
    A simple harmonic motion is represented by $y\, = 5\,(\sin \,3\pi t\, + \,\sqrt 3 \,\cos \,3\pi t)\,cm$ The amplitude and time period of the motion are
    View Solution
  • 6
    Consider the following statements. The total energy of a particle executing simple harmonic motion depends on its

    $(1)$ Amplitude      $(2) $ Period         $(3)$ Displacement

    Of these statements

    View Solution
  • 7
    The amplitude of an oscillating simple pendulum is $10\,cm$ and its period is $4\, sec$. Its speed after $1\, sec$ after it passes its equilibrium position, is ... $m/s$
    View Solution
  • 8
    A particle of mass $m$ is attached to one end of a mass-less spring of force constant $k$, lying on a frictionless horizontal plane. The other end of the spring is fixed. The particle starts moving horizontally from its equilibrium position at time $t=0$ with an initial velocity $u_0$. When the speed of the particle is $0.5 u_0$, it collies elastically with a rigid wall. After this collision :

    $(A)$ the speed of the particle when it returns to its equilibrium position is $u_0$.

    $(B)$ the time at which the particle passes through the equilibrium position for the first time is $t=\pi \sqrt{\frac{ m }{ k }}$.

    $(C)$ the time at which the maximum compression of the spring occurs is $t =\frac{4 \pi}{3} \sqrt{\frac{ m }{ k }}$.

    $(D)$ the time at which the particle passes througout the equilibrium position for the second time is $t=\frac{5 \pi}{3} \sqrt{\frac{ m }{ k }}$.

    View Solution
  • 9
    In an angular $SHM$ angular amplitude of oscillation is $\pi $ $rad$ and time period is $0.4\,sec$ then calculate its angular velocity at angular displacement $ \pi/2 \,rad$. ..... $rad/sec$
    View Solution
  • 10
    A linear harmonic oscillator of force constant $2 \times {10^6}N/m$ and amplitude $0.01\, m$ has a total mechanical energy of $160$ joules. Its
    View Solution