A linear harmonic oscillator of force constant $2 \times {10^6}N/m$ and amplitude $0.01\, m$ has a total mechanical energy of $160$ joules. Its
IIT 1989,AIPMT 1996, Medium
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(d) Harmonic oscillator has some initial elastic potential energy and amplitude of harmonic variation of energy is $\frac{1}{2}K{a^2} = \frac{1}{2} \times 2 \times {10^6}{(0.01)^2} = 100\,J$
This is the maximum kinetic energy of the oscillator. Thus ${K_{\max }} = 100J$
This energy is added to initial elastic potential energy may give maximum mechanical energy to have value $160J$.
This is the maximum kinetic energy of the oscillator. Thus ${K_{\max }} = 100J$
This energy is added to initial elastic potential energy may give maximum mechanical energy to have value $160J$.
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