MCQ
The total number of electrons present in all the $p$-orbitals of bromine are
- A$5$
- B$18$
- ✓$17$
- D$35$
✓
Answer
Correct option: C.
$17$
c
(c) The atomic number of bromine is $35$ and the electronic configuration of $Br$ is $B{r_{35}} = \,1{s^2},\,2{s^2},\,2{p^6},\,3{s^2},\,3{p^6},\,3{d^{10}},\,4{s^2},\,4{p^5}$
(c) The atomic number of bromine is $35$ and the electronic configuration of $Br$ is $B{r_{35}} = \,1{s^2},\,2{s^2},\,2{p^6},\,3{s^2},\,3{p^6},\,3{d^{10}},\,4{s^2},\,4{p^5}$
total electron present in $p-$ orbitals of $Br$ is -
$2{p^6} + 3{p^6} + 4{p^5} = 17.$
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