MCQ
An aqueous solution of oxalic acid dihydrate contains its $6.3\, g$ in $250\, ml$. The volume of $0.1\, N\, NaOH$ required to completely neutralize $10\, ml$ of this solution .............. $\mathrm{ml}$
- A$4$
- B$20$
- C$2$
- ✓$40$
$ = \frac{{6.3 \times 1000}}{{63 \times 250}} = 0.4\,N$
Now from
${N_1}{V_1} = {N_2}{V_2}$
$0.4 \times 10 = 0.1 \times V_2$
$V_2 = 40\,mL$
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