MCQ
The total number of lone pairs of electrons in $N _2 O _3$ is
- A$5$
- B$6$
- C$7$
- ✓$8$

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if $T_1 < T_2$ then $X$ and $Y$ respectively are
[Given : $h =6.63 \times 10^{-34}\, J \,s$, and $c =3 \times 10^{8} \,m\, s ^{-1}$ ]
$\begin{array}{*{20}{c}}
{\,\,\,\,\,H} \\
{\,\,\,\,\,\,|} \\
{C{H_3}C{H_2} - N - CHO}
\end{array}$

$(i)$ In pure water
$(ii)$ In presence of $0.1\ M AgNO_3$
$(iii)$ In presence of $2\ M aq.$ solution of $KCN$
$(iv)$ In presence of $ 1\ M aq$. solution of $Ca(CN)_2$
$(v)$ In presence of $2\ M aq.$ solution of $NH_3$
(Assuming $100\%$ dissociation of $AgNO_3, KCN$ and $Ca(CN)_2)$ and complex formation with $NH_3$ and $CN^-$ will take place.