MCQ
In the reaction product $D$ is $\begin{array}{*{20}{c}}
  {C{H_2}} \\ 
  {||\,\,\,\,\,\,\,\,} \\ 
  {C{H_2}} 
\end{array}$ $\xrightarrow{{B{r_2}/CC{l_4}}}A\xrightarrow{{KCN}}B\xrightarrow{{{H_3}{O^ + }}}C\xrightarrow{\Delta }D$
  • A

  • B
    $H_3CH_2COOH$

  • D
    $CH_2OHCH_2CN$

Answer

Correct option: C.

c
$\begin{array}{*{20}{c}}
  {C{H_2}} \\ 
  {||\,\,\,\,\,\,} \\ 
  {C{H_2}} 
\end{array}\xrightarrow{{B{r_2}/CC{l_4}}}\begin{array}{*{20}{c}}
  {C{H_2} - Br} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_2} - Br} 
\end{array}$ $\xrightarrow{{KCN}}\begin{array}{*{20}{c}}
  {C{H_2} - CN} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_2} - CN} 
\end{array}\xrightarrow{{{H_3}{O^ \oplus }}}$ $\begin{array}{*{20}{c}}
  {C{H_2} - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_2} - COOH} 
\end{array}\xrightarrow[\Delta ]{{ - {H_2}O}}$ (figure)

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