The total power dissipated in watts in the circuit shown is ............. $W$
A$4$
B$16$
C$40$
D$54$
Medium
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D$54$
d $\mathrm{R}_{\mathrm{eq}}=6 \Omega \quad \mathrm{P}=\frac{\mathrm{V}^{2}}{\mathrm{R}_{\mathrm{eq}}}$
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