and $y=\overline{A . C}$
$\begin{array}{l|l|l|l|l|}\hline A & {\mathrm{B}} & {\mathrm{C}=(\mathrm{A}+\mathrm{B})} & {\mathrm{A} \mathrm{C}} & {\mathrm{y}=\overline{\mathrm{A} . \mathrm{C}}} \\ \hline 0 & {0} & {0} & {0} & {1} \\ {0} & {1} & {1} & {0} & {1} \\ {1} & {0} & {1} & {1} & {0} \\ {1} & {1} & {1} & {1} & {0} \\ \hline\end{array}$
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[Given: $\pi=22 / 7, g=10 ms ^{-2}$, density of water $=1 \times 10^3 kg m ^{-3}$, viscosity of water $=1 \times 10^{-3} Pa$-s.]
$(A)$ The work done in pushing the ball to the depth $d$ is $0.077 J$.
$(B)$ If we neglect the viscous force in water, then the speed $v=7 m / s$.
$(C)$ If we neglect the viscous force in water, then the height $H=1.4 m$.
$(D)$ The ratio of the magnitudes of the net force excluding the viscous force to the maximum viscous force in water is $500 / 9$.