MCQ
The TSA of a solid cylinder whose radius is half of its height h is equal to:
  • A
    $\frac{2}{3}\pi\text{h}\text{ sq.units}$
  • B
    $\frac{2}{3}\pi\text{h}^2\text{ sq.units}$
  • C
    $\frac{3}{2}\pi\text{h}\text{ sq.units}$
  • D
    $\frac{3}{2}\pi\text{h}^2\text{ sq.units}$

Answer

  1. $\frac{3}{2}\pi\text{h}^2\text{ sq.units}$

Solution:

Here $\text{r}=\frac{\text{h}}{2}$

$\therefore$ TSA of a soild cylinder $=2\pi\text{r}(\text{r}+\text{h})$

 $=2\pi\times\frac{\text{h}}{2}\Big(\frac{\text{h}}{2}+\text{h}\Big)$

$=\pi\text{h}\Big(\frac{\text{3h}}{2}\Big)$

$=\frac{3}{2}\pi\text{h}^2\text{ sq.units}$

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