MCQ
The TSA of a solid hemisphere of diameter 2cm is:
- A$12\pi\text{cm}^2$
- B$8\pi\text{cm}^2$
- C$3\pi\text{cm}^2$
- D$4\pi\text{cm}^2$
✓
Answer
- $3\pi\text{cm}^2$
Solution:
Diameter of hemisphere = 2cm
then Radius
$\frac{2}{2}=1\text{cm}$$\therefore3\pi\text{r}^2=3\pi(1)^2=3\pi\text{cm}^2$
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