MCQ
The two compounds given below are


- ✓enantiomers
- Bidentical
- Coptically inactive
- Ddiastereomers

$R S \rightarrow S R$
$S R \rightarrow R S$
Diasteromers:
$R R \rightarrow S S$
$S S \rightarrow R R$
They are Diasteromers
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| List$-I$ | List$-II$ |
| $(I)$ $XeF_4$ | $(A)$ See-saw |
| $(II)$ $I_3^-$ | $(B)$ Tetra hedral |
| $(III)$ $XeO_2F_2$ | $(C)$ Bond angle $90^o$ |
| $(IV)$ $SO_4^{2-}$ | $(D)$ Linear |


$STATEMENT$-$2$: $o$-Hydroxybenzoic acid has intramolecular hydrogen bonding.