- AOhm
- BVolt
- ✓Ampere
- DCoulomb
Since, the charge is measured in coulombs and time in seconds, the electric current unit is Coulomb $/$ Sec $( C / s )$ Where, coulomb/sec is defined as Ampere
So the Ampere is the SI unit of the current.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$Ag\left( s \right)\left| {AgBr\left( s \right)\,\left| {B{r^ - }\left( {0.01\,M} \right)} \right|\,\left| {{I^ - }\left( {0.02\,M} \right)} \right|\,AgI\left( s \right)} \right|Ag\left( s \right)$
the correct information is
[Given : $K_{sp}\,\left( {AgBr} \right) = 4 \times {10^{ - 13}}$ ,
$K_{sp}\,\left( {AgI} \right)$ $ = 8 \times {10^{ - 17}},\frac{{2.303\,RT}}{F} = 0.06\,V,\,\log \,2 = 0.3]$

$A \rightarrow B; \ \ \ K_1 = 10^{15}\ exp.\ \left( {\frac{{ - 2000}}{T}} \right)$
$C \rightarrow D;\ \ \ K_2 = 10^{14}\ exp. \ \left( {\frac{{ - 1000}}{T}} \right)$
The temperature at which $K_1 = K_2$ is ........... $K$ ($exp. = e$)